loiwtjsf
Dołączył: 30 Sie 2010
Posty: 1562
Przeczytał: 0 tematów
Ostrzeżeń: 0/5 Skąd: ewcinl
|
Wysłany: Nie 16:33, 19 Gru 2010 Temat postu: air jordan shoes cheap Torsion axis determined rad |
|
|
Torsion axis determined radial distribution method of injury
Between the force and shear strain values of a single, solid shaft with radius r the shear stress at the time that is equal to the corresponding cylinder wall shear stress, the relationship is as follows: type: l l a a a AA ∞ Lu When = Half (5) L,-a where G is the shear elastic non-destructive material amount of chess, G is the shear elastic damaged materials chess set, that is, unloading shear modulus, dA is the elastic bands = Beng (6) was established : (s + aM) = c where: R = (+ d_) t = per 1 (da-d,) ( (9) Manlan interest Jue Man Yi's wife then usurped the throne, limonene shear and pure shear damage between the single value D, the Hui Lei Xiao Gu 7 Sharp scissors. The twist angle; T-wall shear specimen both I: Ma a test group of thin-walled circular garland added twist when the killer called the dry r work / call w, TIAN Qiu Ju. I. Anterior wall of the cylindrical specimen shear stress. Thin cylinder when the corresponding pure-shear injury. Based on the above analysis, we only need to torsion angle determination of the sample is too thin cylinder of pure shear can damage factor D by (6) is converted into solid shaft radius r at the cylinder torsion shear strain and angle of shear strain when the twist angle equal to the corresponding currency, this time solid shaft twist angle of radius r at the damage factor for the coin cylinder is the twist angle of the damage factor for the Sapporo D. Thus,[link widoczny dla zalogowanych], we can sample by measuring cylinder D,. Curve to calculate Ds solid shaft outer curve of the material, but also because when the twist angle is constant, the radial solid shaft torsion shear strain and the solid shaft radius Fu linear system, so solid shaft damage after torsion radial distribution graphics and solid shaft outer curve of the material exactly the same shape of Dz, but also the determination and thin-walled cylinder specimens Dz. We just need to be consistent with curve curve abscissa currency by the twist angle. Into a solid shaft radius r. Tide test example we first use of thin-walled steel cylinder 45,[link widoczny dla zalogowanych], to determine who the Ds a curve, the sample size for the thin cylinder: diameter da = 16.00mm, inner diameter d, = 15.00ram thin a cylindrical working length lo 7.50ram, test system in order to eliminate the impact of eccentricity on the test used to eliminate the eccentric concentric cage effects in thin-walled cylinder specimen cut out all the marks is to ensure the twist angle of the bow 【stretching apparatus installation accuracy and repeat the installation accuracy. In order to improve test accuracy and reduce the difficulty of processing samples using thin-walled cylinder bore-centering positioning system device, see the detailed test [2]. In this experiment, NJ-IOOB type made to reverse the test machine, torsion angle extensometer using Instron ~ pull bow twisted Recovering 【extension instrument. Using formula (2) and Figure 1 rinse test method D-and Sapporo obtained the results shown in Table 1 and Figure 3. Today there is a solid torsion shaft, the diameter D = 35mm, length L = l00mm, when the torsion angle = 200 'when the calculated radial distribution of damage: from (6), (, we have: Table 1. (Degrees) 0.1 (elastic) l add: 0303540I45 elixir MMr (kg, m) 1l1l111f11lA × 10q (degrees) 4.000l4.3T54l1T4.66T535.083l5.1255.4175.583Di0l0.0880. G940.1430.2lO0.213l0.2200.262 by the. 2840--. . * Figure 3 towels. And D, curve R = (+ d,) = 7-75mm at this time we only need the horizontal axis in Figure 3,[link widoczny dla zalogowanych], tie into r, and D, leaf curve just take D,. Curve (Figure 3) 0 ~ 33.9 that period - so we get the solid torsion moment of the injury in the whip radial distribution curve, shown in Figure 4 if we only know that being suffered by a solid shaft torsional torque - We can use the formula ∞, ∽ obtain the corresponding thin cylinder torque Mo, then the thin cylinder M ・ n Fig been corresponding with the solid shaft twist angle. . So that we can obtain the same damage by the distribution of torque solid shaft. r (ram) 4r circle with the D | 1 Introduction curve four samples using thin-walled cylinder to reverse the determination of the D-curve,[link widoczny dla zalogowanych], we can get the sentence of any material, any diameter solid shaft torsion in the plastic stage of the damage path at any time the distribution curve. 2 article in the cylinder test, the effective measures taken to ensure the accuracy of the test. References 1.7canLema | t-kun. AContinousDamageMechanicsModelforDuctiIeF ~ 'aCtUl ~,[link widoczny dla zalogowanych], ffourn * lofEngineer-ingMat ~ rLdse. udTechnology. JANUARY198b_vol107/8g2 Wang Wan. Ductile fracture curve of the genus barrier. Wo Shi, Zhejiang University dissertation. 1989-45--
相关的主题文章:
[link widoczny dla zalogowanych]
[link widoczny dla zalogowanych]
[link widoczny dla zalogowanych]
Post został pochwalony 0 razy
|
|